Gaseous StateHard

Question

For one mole of a van der Waals gas when b = 0 and T = 300 K, the PV vs. 1/V plot is shown below. The value of the van der Waals constant a (atm.litre2mol-2) is
                 

Options

A.1.0
B.4.5
C.1.5
D.3.0

Solution

               
van der Waals equation for 1 mole of real gas is,
(V - b) = RT
but, b = 0 (given)
(V) = RT
∴ PV = - a × + RT             .....(i)
y = mx + c
Slope = tan (π - θ) = - a
So, tan θ = a =
or tan θ =

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