Gaseous StateHard
Question
At 100oC and 1 atm if the density of the liquid water is 1.0 g cm-3 and that of water vapour is 0.0006 g cm-3 then the volume occupied by waetr molecules in 1 L of steam at this tem perature is :
Options
A.6 cm3
B.60 cm3
C.0.6 cm3
D.+ 6.8 cm3
Solution
Mass of 1000 mL steam = 1000 × 0.0006
= 0.6g
∴ Volume of liquid water =
= 0.6 cm3
= 0.6g
∴ Volume of liquid water =
= 0.6 cm3 Create a free account to view solution
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