Mole ConceptHard
Question
A bag contains 0.32 g of oxygen. The same volume of an unknown gas A under similar condition of temperature and pressure is present in another container having mass 0.26 gm. If C and H are in 1 : 1 ratio in compound. The molecular formula of the compound is -
Options
A.C2H2
B.C4H4
C.C3H4
D.CH
Solution
Moles of O2 in bag A = 0.32/32 = 0.01 mol
Same volume of unknown gas = = 0.01mol
0.01 mol of unknown gas A = 0.26 g
1 mol of unknown gas A =
= 26 g
Mwt of unknown gas A = 26 g
Empirical formula = CH
Empirical formula weight = 12 + 1 = 13 g
n =
= 2
Molecular formula = (CH)2 = C2H2.
Same volume of unknown gas = = 0.01mol
0.01 mol of unknown gas A = 0.26 g
1 mol of unknown gas A =
= 26 gMwt of unknown gas A = 26 g
Empirical formula = CH
Empirical formula weight = 12 + 1 = 13 g
n =
= 2Molecular formula = (CH)2 = C2H2.
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