Mole ConceptHard
Question
A compound has carbon, hydrogen and oxygen in 3: 3: 1 atomic ratio. If the number of moles in 1 g of the compound is 6.06 × 10−3, then the molecular formula of the compound will be
Options
A.C3H3O
B.C6H6O2
C.C9H9O3
D.C12H12O4
Solution
Molecular mass of the compound $= \frac{1}{6.06 \times 10^{- 3}} \approx 165$
Empirical formula mass = 3 × 12 + 3 × 1 + 1 × 16 = 55
Now, n = $\frac{165}{55}$= 3 and hence, the molecular formula = (C3H3O)3 = C9H9O3.
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