Ionic EquilibriumMedium
Question
At 80oC, distilled water (H3O+) has concentration equal to 1 × 10-6 mole/liter. the value of Kw, at this tempreature will be
Options
A.1 × 10-6
B.1 × 10-12
C.1 × 10-9
D.1 × 10-15
Solution
[H2O+] = [H+] = 10-6
Kw = [H+] = 10-6
In pure water, [H+] = [OH-]
So [OH-] = [H3O+] = 10-6
Kw = [10-6][10-6] = 10-12
Remember that Kw increases with increase in temperaturer
Kw = [H+] = 10-6
In pure water, [H+] = [OH-]
So [OH-] = [H3O+] = 10-6
Kw = [10-6][10-6] = 10-12
Remember that Kw increases with increase in temperaturer
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