Ionic EquilibriumHard

Question

pH of a saturated solution of Ba(OH)2 is 12. The value of solubility product (Ksp) of Ba(OH)2 is

Options

A.5.0 × 10-6
B.3.3 × 10-7
C.5.0 × 10-7
D.4.0 × 10-6

Solution

pH = 12
pOH = 12          ⇒     [OH-] = 10-2 
Ba(OH)2 ⇋ Ba2+ + 2OH-         ⇒ 2x = 10-2
                        x           2x           ⇒ x = 5 × 10-3
Ksp = x(2x)2 = 5 × 10-3 × (10-2)2 = 5 × 10-7

Create a free account to view solution

View Solution Free
Topic: Ionic Equilibrium·Practice all Ionic Equilibrium questions

More Ionic Equilibrium Questions