ThermodynamicsHard
Question
During isothermal expansion of the mole of an ideal gas from 10 atm at 273K, the workdone is [gas constant = 2]:
Options
A.-895.8 cal
B.- 1172.6 cal
C.- 1257.43 cal
D.- 1499.6cal
Solution
Work done in expansion of gas
= - 2.303 nRT log
= -1257.43cal.
= - 2.303 nRT log
= -1257.43cal.
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