ThermodynamicsEasy

Question

The following reaction is performed at 298 K. 2NO(g) + O2(g) ⇋ 2NO2(g) The standard free energy of formation of NO(g) is 86.6 kJ/mol at 298 K. What is the standard free energy of formation of NO2(g) at 298 K ? (Kp = 1.6 × 1012)

Options

A.86600 -
B.0.5[2 × 86,600 − R(298) ln (1.6 × 1012)]
C.R(298) ln(1.6 × 1012) − 86600
D.86600 + R (298) ln(1.6 × 1012)

Solution

ᐃGorxn = 2ᐃGof (NO2 ) − 2ᐃGof (NO)
ᐃGof (NO2) = [ᐃGorxn + 2ᐃGof (NO)]
ᐃGof(NO2) = 0.5[2 × 86600 − R(298) ln (1.6 × 1012)]

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