ThermodynamicsHard
Question
Standard entropy of X2, Y2 and XY2 are 60, 40 and 50 JK-1mol-1, respectively. For the reaction,
, ᐃH = - 30 kJ, to be at equilibrium, the temperature will be
, ᐃH = - 30 kJ, to be at equilibrium, the temperature will beOptions
A.1250 K
B.500 K
C.750 K
D.1000 K
Solution
ᐃSreaction = 50 -
= - 40 j mol-1 ᐃG = ᐃH - TH - TᐃS
at equilibrium ᐃG = 0
ᐃH = TᐃS
30 × 103 = T × 40
⇒ T = 750 K
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