Ionic EquilibriumHard
Question
What is the pH value of M H2SO4 ?
Options
A.0
B.-0.213
C.-2
D.-0.3010
Solution
H2So4 → 2H+ + SO42-
1M 2M 1M
[H+] = 2
pH = -log[H+] = - log2
= 0.3010 [∵ log 2 = 0.3010]
1M 2M 1M
[H+] = 2
pH = -log[H+] = - log2
= 0.3010 [∵ log 2 = 0.3010]
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