NEETIonic EquilibriumHard
Question
The solubility product of AgCl is 10-10. The minimum volume (in L) of water required to dissolve 1.722 mg of AgCl is (molecular weight of AgCl = 143.5).
Options
A.10 lt.
B.2.2 lt.
C.1.2 lt.
D.20 lt.
Solution
Solubilility of AgCl in water = 10-5 mol/lt.
so volume of water required =
= 1.2 lt.
so volume of water required =
= 1.2 lt.Create a free account to view solution
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