NEETIonic EquilibriumHard
Question
The solubility product of AgCl is 10-10. The minimum volume (in L) of water required to dissolve 1.722 mg of AgCl is (molecular weight of AgCl = 143.5).
Options
A.10 lt.
B.2.2 lt.
C.1.2 lt.
D.20 lt.
Solution
Solubilility of AgCl in water = 10-5 mol/lt.
so volume of water required =
= 1.2 lt.
so volume of water required =
= 1.2 lt.Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
Acetic acid and propionic acid have Ka values 1.75 × 10-5 and 1.3 × 10-5 respectively at a certain temperature...The pH of an acid buffer can be raised by 2 units by...Arrange the following resultant mixtures in increasing order of their pH values A. 10 mL 0.2 M Ca(OH)₂ + 25 mL 0.1 M HCl...20 mL of a weak monobasic acid (HA) requires 20 mL 0.2 M NaOH for complete titration. If pH of solution upon addition of...The solubility product of AgCl is 1.0 × 10–10. The equilibrium constant of the reactionAgCl(s) + Br–$\rightleftharpoons$...