Chemical BondingHard
Question
Select the rate law that corresponds to the data shown for the following reaction
Exp. no. [A0] (M) [B0] (M) Initial rate (Ms−1)
1 0.012 0.035 0.1
2 0.024 0.070 0.8
3 0.024 0.035 0.1
4 0.012 0.070 0.8
Options
A.r = K[B]3
B.r = K[B]4
C.r = K[A][B]3
D.r = K[A]2[B]3
Solution
r = K[A]x [B]y
Exp (1) ÷ Exp (3): $\frac{0.1}{0.1} = \frac{K(0.012)^{x}(0.035)^{y}}{K(0.024)^{x}(0.035)^{y}} \Rightarrow x = 0$
Exp (2) ÷ Exp (3): $\frac{0.8}{0.1} = \frac{K(0.024)^{x}(0.070)^{y}}{K(0.024)^{x}(0.035)^{y}} \Rightarrow y = 3$
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