Ionic EquilibriumHard
Question
The pH of solution containing 0.10 M sodium acetate and 0.03 M acetic acid is
(pKa for CH3COOH = 4.57)
(pKa for CH3COOH = 4.57)
Options
A.0.09
B.6.09
C.5.09
D.7.09
Solution
According to henderson equation, pH of acidic buffer is given as
pH = pKa + log
= 4.57 + log
= 4.57 + [log 10 - log 3]
= 4.57 + log 3.33
= 4.57 = 0.52 = 5.09
pH = pKa + log
= 4.57 + log
= 4.57 + [log 10 - log 3]
= 4.57 + log 3.33
= 4.57 = 0.52 = 5.09
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