Ionic EquilibriumHard
Question
A saturated solution of silver benzoate (AgOCOC6H5) has pH of 8.6. Ka for benzoic acid is 5.0 × 10–5. The value of Ksp for silver benzoate is (log 2 = 0.3)
Options
A.8.0 × 10−2
B.6.4 × 10−3
C.6.4 × 10−4
D.0.282
Solution
$Tl_{2}S(S) \rightleftharpoons \underset{2SM}{2Tl^{+}} + \underset{x}{S^{2 -}}$
$\underset{x\text{ M}}{S^{2 -}} + H_{2}O \rightleftharpoons \underset{\text{SM}}{HS^{-}} + \underset{\text{SM}}{OH^{-}};K_{h} = \frac{Kw}{K_{a_{2}}} $$${\frac{10^{- 14}}{10^{- 14}} = \frac{2 \times 10^{- 6} \times 2 \times 10^{- 6}}{x} \Rightarrow x = 4 \times 10^{- 12} }{\therefore K_{sp} = \left( 2 \times 2 \times 10^{- 6} \right)^{2} \times 4 \times 10^{- 12} = 6.4 \times 10^{- 23}}$$
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