ElectrochemistryHard
Question
The oxidation states of iodine in HIO4, H3IO5 and H5IO6 are respectively
Options
A.+1, +3, +7
B.+7, +7, +3
C.+7, +7, +7
D.+7, +5, +3
Solution
Calculating the oxidation states of I, we get
H5IO6; 5 + x - 12 = 0 or x = + 7
H3IO5; 3 + x - 10 = 0 or x = + 7
HIO4; 1 + x - 8 = 0 or x = + 7
H5IO6; 5 + x - 12 = 0 or x = + 7
H3IO5; 3 + x - 10 = 0 or x = + 7
HIO4; 1 + x - 8 = 0 or x = + 7
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