ElectrochemistryHard
Question
Given the data at 25oC,
Ag + I- → Agl + e- ; Eo = 0.152 V
Ag → Ag+ + e- : Eo = - 0.800 V
What is the value of log Ksp for AgI ?
Ag + I- → Agl + e- ; Eo = 0.152 V
Ag → Ag+ + e- : Eo = - 0.800 V
What is the value of log Ksp for AgI ?
Options
A.- 8.12
B.+8.612
C.- 37.83
D.- 16.13
Solution
AgI(s) + e- ⇋ Ag(s) + I- ; Eo = - 0.152
Ag(s) → Ag+ + I- ; Eo = - 0.8
AgI(s) → Ag+ + I- ; Eo = - 0.952
Eocell =
log K
- 0.952 =
log Ksp
log Ksp = -
= - 16.135
Ag(s) → Ag+ + I- ; Eo = - 0.8
AgI(s) → Ag+ + I- ; Eo = - 0.952
Eocell =
log K- 0.952 =
log Ksplog Ksp = -
= - 16.135Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
The standard reduction potentials E° of the following systems are System E° (volts)(i) MnO4- + 8H+ + 5e- → Mn2+ + ...A lead storage cell is discharged which causes the H2SO4 electrolyte to change from a concentration of 40% by weight (de...The standard reduction potentials of Cu2+|Cu and Cu2+|Cu+ are 0.337 V and 0.153 V, respectively. The standard electrode ...For the cell Zn|Zn2+||Cu2+|Cu, if the concentration of both, Zn2+ and Cu2+ ions are doubled, the EMF of the cell...Given below are the half-cell reactions Mn2+ + 2e- → Mn ; Eo = - 1.18 V (Mn3+ + e- → Mn2+) ; Eo = + 1.51 V T...