ElectrochemistryHard
Question
Given the data at 25oC,
Ag + I- → Agl + e- ; Eo = 0.152 V
Ag → Ag+ + e- : Eo = - 0.800 V
What is the value of log Ksp for AgI ?
Ag + I- → Agl + e- ; Eo = 0.152 V
Ag → Ag+ + e- : Eo = - 0.800 V
What is the value of log Ksp for AgI ?
Options
A.- 8.12
B.+8.612
C.- 37.83
D.- 16.13
Solution
AgI(s) + e- ⇋ Ag(s) + I- ; Eo = - 0.152
Ag(s) → Ag+ + I- ; Eo = - 0.8
AgI(s) → Ag+ + I- ; Eo = - 0.952
Eocell =
log K
- 0.952 =
log Ksp
log Ksp = -
= - 16.135
Ag(s) → Ag+ + I- ; Eo = - 0.8
AgI(s) → Ag+ + I- ; Eo = - 0.952
Eocell =
log K- 0.952 =
log Ksplog Ksp = -
= - 16.135Create a free account to view solution
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