ElectrochemistryEasy
Question
Both oxidation and reduction takes place in :
Options
A.NaBr + Hcl → NaCl+ HBr
B.HBr + AgNO3 → AgBr + NHO3
C.H2 + Br2 → 2HBr
D.CaO + H2So4 → CaSO4 = H2O
Solution
In the reaction :
H2 + Br2 → 2HBr
Oxidation number of H in H2 is zero whereas its value is + 1 in HBr; similarly oxidation number of Br in Br2 in zero wheras its value is - 1 in HBr. So, So here H is oxiddised and Br reduced. in all other reactions, there in no cahnge in the oxidation number of any element.
H2 + Br2 → 2HBr
Oxidation number of H in H2 is zero whereas its value is + 1 in HBr; similarly oxidation number of Br in Br2 in zero wheras its value is - 1 in HBr. So, So here H is oxiddised and Br reduced. in all other reactions, there in no cahnge in the oxidation number of any element.
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