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Question

Some standard electrode potentials are given:

Fe2+ + 2e− → Fe; E° = −0.440 V

Fe3+ + 3e− → Fe; E° = −0.036 V

The standard electrode potential for: Fe3+ + e− → Fe2+, is

Options

A.−0.476 V
B.−0.404 V
C.+0.988 V
D.+0.772 V

Solution

$E_{Fe^{3 +}|Fe^{2 +}}^{o} = \frac{3 \times E_{Fe^{3 +}|Fe}^{o} - 2 \times E_{Fe^{2 +}|Fe}^{o}}{3 - 2} = + 0.772\text{ V}$

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