ElectrochemistryHard
Question
During the electrolysis of an aqueous salt solution, the pH in the space near one of the electrode was increased and the other one was decreased. The salt solution was
Options
A.NaCl (very dilute)
B.ZnCl2
C.NaCl (Conc.)
D.Cu(NO3)2
Solution
For very dilute NaCl solution,
Cathode: $2H_{2}O(l) + 2e^{-} \rightarrow H_{2}(g) + 2OH^{-}(aq);P^{H} \uparrow$
Anode: $2H_{2}O(l) \rightarrow O_{2}(g) + 4H^{+}(aq) + 4e^{-};P^{H} \downarrow$
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