ElectrochemistryMedium

Question

During the electrolysis of an aqueous salt solution, the pH in the space near one of the electrode was increased and the other one was decreased. The salt solution was

Options

A.NaCl (very dilute)
B.ZnCl2
C.NaCl (Conc.)
D.Cu(NO3)2

Solution

For very dilute NaCl solution,

Cathode: $2H_{2}O(l) + 2e^{-} \rightarrow H_{2}(g) + 2OH^{-}(aq);P^{H} \uparrow$

Anode: $2H_{2}O(l) \rightarrow O_{2}(g) + 4H^{+}(aq) + 4e^{-};P^{H} \downarrow$

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