ElectrochemistryEasy
Question
Through a solution of CuSO4 a current of 3 amperes was passed for 2 hours. At cathode 3 g of Cu2+ ions were discharged. The current efficiency is [At. wt. of Cu = 63.5]
Options
A.33.3%
B.42.2%
C.48.7%
D.54.4%
Solution
According to law of electrolysis, Mass deposited (m) - Z i t
or i =
Here, m = 3g, t = 2 t = 2 × 60 × 60 = 7200sec
Z =
; Eq. wt = 
∴ i =
= 1.266A
Efficiency of current
=
× 100
=
× 100 = 42.22%
or i =
Here, m = 3g, t = 2 t = 2 × 60 × 60 = 7200sec
Z =
; Eq. wt = ∴ i =
= 1.266A Efficiency of current
=
× 100=
× 100 = 42.22%Create a free account to view solution
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