ElectrochemistryHard
Question
A dilute aqueous solution of Na2SO4 is electrolysed using platinum electrodes. The products at the anode and cathode are :
Options
A.O2, H2
B.S2O82-, Na
C.O2, Na
D.S2O82-, H2
Solution
At anode : Because discharge potential of OH- is less than SO42-, so OH- is discharged in preference over SO42-
2OH- → H2O +
O2 + 2e-
At cathode : Two iones Na+ and H+ are available to get reduced at cathode, but discharge potential of H+ is less than Na+, so H+ is reduced in preference over Na+
2H+ + 2e- → H2
Na+ + e- → Na
2OH- → H2O +
O2 + 2e-At cathode : Two iones Na+ and H+ are available to get reduced at cathode, but discharge potential of H+ is less than Na+, so H+ is reduced in preference over Na+
2H+ + 2e- → H2
Na+ + e- → Na
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Given:H2O2 → O2 + 2H+ + 2e- E- = - 0.69 VH2O2 + 2H+ + 2e- → 2H2O E- = - 1.77 VI- → I2 + 2e-Which of th...Zn + Cu2+(aq) ⇋ Cu + Zn2+(aq)Reaction quotient is Q = . Variation of Ecell with log Q is of the type with OA = 1.1...The standard potentials of MnO4−|Mn2+ and MnO2|Mn2+ electrodes in acid solution are 1.51 and 1.23 V, respectively. Stand...The metal that cannot be obtained on reduction of its oxide by aluminium is...The reaction: H2(g) + 2AgCl(s) → 2H+ (aq) + 2Cl− (aq) + 2Ag(s) occurs in the galvanic cell...