ElectrochemistryMedium
Question
A dilute aqueous solution of Na2SO4 is electrolysed using platinum electrodes. The products at the anode and cathode are :
Options
A.O2, H2
B.S2O82-, Na
C.O2, Na
D.S2O82-, H2
Solution
At anode : Because discharge potential of OH- is less than SO42-, so OH- is discharged in preference over SO42-
2OH- → H2O +
O2 + 2e-
At cathode : Two iones Na+ and H+ are available to get reduced at cathode, but discharge potential of H+ is less than Na+, so H+ is reduced in preference over Na+
2H+ + 2e- → H2
Na+ + e- → Na
2OH- → H2O +
O2 + 2e-At cathode : Two iones Na+ and H+ are available to get reduced at cathode, but discharge potential of H+ is less than Na+, so H+ is reduced in preference over Na+
2H+ + 2e- → H2
Na+ + e- → Na
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