Gaseous StateHard
Question
28. Gold has a face centered cubic lattice with an edge length of the unit cube of 407 pm. Assuming the closest packing the diameter of the gold atom is
Options
A.576.6 pm
B.287.8 pm
C.352.5 pm
D.704.9 pm
Solution
For fcc lattice,
4 r = diagonal of the face = a√2
or 2r = diameter
=
= 287.8pm
4 r = diagonal of the face = a√2
or 2r = diameter
=
= 287.8pmCreate a free account to view solution
View Solution FreeMore Gaseous State Questions
At what temperature will the total KE of 0.3 mol of He be the same as the total KE of 0.40 mol of Ar at 400 K ?...The given graph represents the variation of Z(compressibility factor ) versus P, for three real gases A, B and C. Identi...50 mL of each gas A and of gas B takes 200 and 150 s respectively for effusing through a pin hole under the similar cond...Compressibility factor for H2 behaving as real gas is :...A gas is heated from 0oC to 100oC at 1.0 atm pressure. If the initial volume of the gas is 10.0, its final volume would ...