Gaseous StateEasy
Question
28. Gold has a face centered cubic lattice with an edge length of the unit cube of 407 pm. Assuming the closest packing the diameter of the gold atom is
Options
A.576.6 pm
B.287.8 pm
C.352.5 pm
D.704.9 pm
Solution
For fcc lattice,
4 r = diagonal of the face = a√2
or 2r = diameter
=
= 287.8pm
4 r = diagonal of the face = a√2
or 2r = diameter
=
= 287.8pmCreate a free account to view solution
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