ElectrochemistryHard
Question
During electrolysis of water the volume of O2 Liberated is 2.24 dm3. The volume of hydrogen liberated, under same condition will be
Options
A.2.24dm3
B.1.12 dm3
C.4.48 dm3
D.0.56 dm3
Solution
Thus, the volume of hydrogen librated is twice that volume of oxygen liberated. When2.24dm3 of oxygen is librated the volume of hydrogen librated will be 2 × 2.4dm3 or 4.48dm3
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