ElectrochemistryHard

Question

Equivalent conductance of an electrolyte containing NaF at infinite dilution is 90.1 Ohm-1 cm2 If NaF is replaced by KF what is the value of equivalent conductance ?

Options

A.90.1 Ohm-1cm2
B.111.2 Ohm-1cm2
C.0
D.222.4 Ohm-1cm2

Solution

Because at infinite dilution the equivalent conductance of strong electrolytes furnishing same number of ions is same.

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