ElectrochemistryHard
Question
A current of 9.65 ampere is passed through the aqueous solution NaCl using suitable electrodes for 1000 s. The amount of NaOH formed during electrolysis is
Options
A.2.0 g
B.4.0 g
C.6.0 g
D.8.0 g
Solution
2H2O + 2e- → H2 + 2OH-
No. of Faraday passed =
= 0.1 F
nOH- formed = 0.1 mol
nNaOH = 0.1 mol ≡ 4 gm.
No. of Faraday passed =
= 0.1 FnOH- formed = 0.1 mol
nNaOH = 0.1 mol ≡ 4 gm.
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