AIPMT | 2014ThermodynamicsMedium
Question
For the reaction, X2O4(l) → 2XO2(g)
ᐃU = 2.1 kcal, ᐃS = 20 cal K-1 at 300 K
Hence, ᐃG is
ᐃU = 2.1 kcal, ᐃS = 20 cal K-1 at 300 K
Hence, ᐃG is
Options
A.2.7 kcal
B.-2.7 kcal
C.9.3 kcal
D.-9.3 kcal
Solution
ᐃH = ᐃU + ᐃngRT = 3.300 kcal
ᐃG = ᐃH - TᐃS = - 2.700 kcal
ᐃG = ᐃH - TᐃS = - 2.700 kcal
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