ThermodynamicsHard
Question
With what minimum pressure must a given volume of an ideal gas ($\gamma$ = 1.4), originally at 400 K and 100 kPa, be adiabatically compressed in order to raise its temperature up to 700 K?
Options
A.708.9 kPa
B.362.5 kPa
C.1450 kPa
D.437.4 kPa
Solution
For minimum pressure, compression should be irreversible.
$\Delta U = w \Rightarrow n.\frac{R}{\gamma - 1}\left( T_{2} - T_{1} \right) = - P_{ext}\left( V_{2} - V_{1} \right) = - P_{2}\left( \frac{nRT_{2}}{P_{2}} - \frac{nRT_{1}}{P_{1}} \right)$
$\text{Or, }\frac{T_{2} - T_{1}}{\gamma - 1} = - \left( T_{2} - T_{1}.\frac{P_{2}}{P_{1}} \right) \Rightarrow \frac{700 - 400}{1.4 - 1} = - \left( 700 - 400 \times \frac{P_{2}}{100} \right) $$$\therefore P_{2} = 362.5\text{ kPa}$$
Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
An ideal gas expands in volume from 1 × 10-3 m3 to 1 × 10-2 m3 at 300 K against a constant pressure of 1 ×...Two moles of an ideal monoatomic gas undergoes a cyclic process ABCA as shown in the figure. What is the ratio of temper...Which of the following graphs between pressure 'P' versus volume 'V' represent the maximum work done?...The incorrect expression among the following is :-...A system absorbs 100 kJ heat in the process shown in the figure. What is ΔU for the system?...