For a reaction A$\rightleftharpoons$B carried out at 27°C, the ratio of equilibrium concentrations o

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For a reaction A$\rightleftharpoons$B carried out at 27°C, the ratio of equilibrium concentrations of the product to reactant changes by a factor of e4 for every

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$\Delta G_{1}^{o} = - RT.\ln K_{1}	ext{ and }\Delta G_{2}^{o} = - RT.\ln K_{2}$$	ext{Now, }\Delta G_{2}^{o} - \Delta G_{1}^{o} = - RT\left\lbrack \ln K_{2} - \ln K_{1} ightbrack $$$= - RT\left\lbrack \ln e^{4} ightbrack$$= –2 × 300 × 4 = –2400 cal

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