AIPMT | 2014Hard
Question
A projectile is fired from the surface of the earth with a velocity of 5 ms-1 and angle θ with the horizontal. Another projectile fired from another planet with a velocity of 3 ms-1 at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in ms-2) is (given g = 9.8 ms-2)
Options
A.3.5
B.5.9
C.16.3
D.110.8
Solution
y = x tan θ - 
For equal trajectories for same angle of projection
= constant
⇒
g′ =
= 3.528 m/s2 = 3.5 m/s2
For equal trajectories for same angle of projection
= constant⇒
g′ =
= 3.528 m/s2 = 3.5 m/s2Create a free account to view solution
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