Hard

Question

A projectile is fired at n angle of 45o with the horizontal. Elevation angle of the projectileat its highest point as seen from the point of projection, is

Options

A.45o
B.60o
C.
D.

Solution

          
Let φ be elevation angle of the projectile at its highest point as seen from the point ofprojection O and θ be an angle of projection with the horizontal.From figure
tan φ =           ......(i)
In case of projectile height, H =
Horizontal range, R =
Substituting these values of H and R in (i), we get


Here, θ = 45o
∴ tan φ tan 45o        (∵ tan 45o = 1)
φ = tan-1

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