Work, Power and EnergyHard
Question
A ball is thrown vertically upward with speed 10 m/sec and it returns to ground withspeed of 8 m/sec. There exists a constant air resistance. The maximum height attained bythe ball will be :
Options
A.4.1 m
B.5.1 m
C.6.1 m
D.7.1 m
Solution
For upwards motion,
m (10)2 = mgH + F × H
For downwards motion, mgH =
m (8)2 + F × H
Solving we get H = 4.1 m
m (10)2 = mgH + F × HFor downwards motion, mgH =
m (8)2 + F × HSolving we get H = 4.1 m
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