Atomic StructureHard
Question
Light of wavelength 4000 
is incident on a metal plate whose work function is 2eV.What is maximum kinetic energy of emitted photoelectron?
is incident on a metal plate whose work function is 2eV.What is maximum kinetic energy of emitted photoelectron?Options
A.0.5eV
B.1.1 eV
C.2.0 eV
D.1.5 eV
Solution
Applying Einstein′s equation
hv = φ +
mv2 = φ + K.E
6.6 × 10-34 ×
= 2 × 1.6 × 10-19 + K.E
× 10-19 = 3.2 × 10-19 + K.E
4.65 × 10-19 = 3.2 × 10-19 + K.E
K.E = (4.95 - 3.2) × 10-19
= 1.75 × 10-19 j.
=
eV = 1.1eV
hv = φ +
mv2 = φ + K.E6.6 × 10-34 ×
= 2 × 1.6 × 10-19 + K.E
× 10-19 = 3.2 × 10-19 + K.E4.65 × 10-19 = 3.2 × 10-19 + K.E
K.E = (4.95 - 3.2) × 10-19
= 1.75 × 10-19 j.
=
eV = 1.1eVCreate a free account to view solution
View Solution FreeMore Atomic Structure Questions
Hard X-rays for the study of fractures in bones should have a minimum wavelength of 1011 m. The accelerating voltage for...If λCu is the wavelength of Kα X-ray line of copper (atomic number 29) and λMo is the wavelength of the K...The wavelength of the first line of Lyman series for hydrogen atom is equal to that of thesecond line of Balmer series f...For a given plate voltage, the plate current in a triode valve is maximum when the potential of...The speed of an electron having a wavelength of 10-10 m is...