Atomic StructureMedium
Question
Light of wavelength 4000 
is incident on a metal plate whose work function is 2eV.What is maximum kinetic energy of emitted photoelectron?
is incident on a metal plate whose work function is 2eV.What is maximum kinetic energy of emitted photoelectron?Options
A.0.5eV
B.1.1 eV
C.2.0 eV
D.1.5 eV
Solution
Applying Einstein′s equation
hv = φ +
mv2 = φ + K.E
6.6 × 10-34 ×
= 2 × 1.6 × 10-19 + K.E
× 10-19 = 3.2 × 10-19 + K.E
4.65 × 10-19 = 3.2 × 10-19 + K.E
K.E = (4.95 - 3.2) × 10-19
= 1.75 × 10-19 j.
=
eV = 1.1eV
hv = φ +
mv2 = φ + K.E6.6 × 10-34 ×
= 2 × 1.6 × 10-19 + K.E
× 10-19 = 3.2 × 10-19 + K.E4.65 × 10-19 = 3.2 × 10-19 + K.E
K.E = (4.95 - 3.2) × 10-19
= 1.75 × 10-19 j.
=
eV = 1.1eVCreate a free account to view solution
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