ThermodynamicsHard

Question

Two identical containers A and B with friction pistons contain the ideal gas at the same temperature and the same volume v. The mass of the gas in A is mA and b in mB. The gas in each cylinder is now allowed to expand isothermally to the same final volume 2v. The changes in pressure in a b are found to be ᐃp and 1.5 ᐃp respectively. Then

Options

A.4mA = 9mB
B.2mA = 3mB
C.3mA = 2mB
D.9mA = 4mB

Solution

The initial pressure in the two containers will be
PA = = mA
PB = = mB
After isothermal expasion, pressure will be
P′B = = mB
P′A = = mA
∴   - ᐃPA = PA - P′A = mA
∴   - ᐃPB = PB - P′B = mB
But ᐃPA = ᐃP and - ᐃPB = 1.5 ᐃ
So, ⇒ - ᐃPA =
mA
or     mA =
∴   3mA = 2mB

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