ThermodynamicsMedium
Question
To rigid boxes containing different ideal gases are placed on a table. Box A contains one mole are placed on a table. Box A contains one mole of nitrogen at temperature T0, while box B contains one mole of helium at temperature 
T0. The boxes are then put into thermal contect with each until the gases reach a common final temprature of the gases, Tf in terms of T0 is
T0. The boxes are then put into thermal contect with each until the gases reach a common final temprature of the gases, Tf in terms of T0 is Options
A.Tf = 
B.Tf = 
C.Tf = 
D.Tf = 
Solution
Heat lost by He = Heat gained by N2
n1Cv1ᐃT1 = n2Cv2 ᐃT2
R[Tf - T0]
7T0 - 3Tf = 5Tf - 5T0
⇒ 12T0 = 8Tf ⇒ Tf =
T0 ⇒ Tf = 
T0
n1Cv1ᐃT1 = n2Cv2 ᐃT2
R[Tf - T0]7T0 - 3Tf = 5Tf - 5T0
⇒ 12T0 = 8Tf ⇒ Tf =
T0 ⇒ Tf = T0Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
A gas speciman in one vessel is expended isothermally to double its volume and a simillar specimen in the second vessel ...n moles of an ideal triatomic linear gas undergoes a process in which the temperature changes with volume as T = k1V2 wh...The volume of a poly-atomic gas compressed adiabatically to of the original volume. If the original pressure of the gas ...In a process on a closed system of ideal gas, the initial pressure and volume is equal to the final pressure and volume...Amount of work which can be obtained from 200 cal heat, will be :...