ThermodynamicsHard
Question
N moles of a monoatomic gas is carried round the reversible rectangular cycle ABCDA as shown in the diagram. The temperature at A is T0. The thermodynamic efficiency of the cycle is:
Options
A.15 %
B.50 %
C.20 %
D.25 %
Solution
Heat absorbed = Work done by gas at = 2P0 (2V0 - V0) = 2PV0V0
Net work done by the gas = Workdone by the gas - Workdone on the gas
= 2P0V0 - P0V0
So efficiency =
× 100 = 50%
Net work done by the gas = Workdone by the gas - Workdone on the gas
= 2P0V0 - P0V0
So efficiency =
× 100 = 50%Create a free account to view solution
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