ThermodynamicsHard
Question
A black body is heated from 27oC to 127oC. The ratio of their energies of radiation emitted will be:
Options
A.9 : 16
B.27 : 64
C.81 : 256
D.3 : 4
Solution
we know that
E = σT4
Where E is rate of emission of radation of a body at temperature T.
E1 = σ(27 + 273)2
E2 = σ(127 + 273)2
E = σT4
Where E is rate of emission of radation of a body at temperature T.
E1 = σ(27 + 273)2
E2 = σ(127 + 273)2
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