Momentum and CollisionMedium
Question
A bomb of mass 3.0kg explodes in air two pieces of masses of masses 2.0kg and 1.0 kg. The smaller mass goes at a speed of two fragments is:
Options
A.1.07kj
B.2.14kj
C.2.4kj
D.4.8kj
Solution
Applying conservation of momentam
2 v = 1 ×80
v = 40 m/sec
total energy of pieces
× 2 × 40 × 40 + × 1 × 80 × 80
= 1600 + 3200 = 4800 J = 4.8kj
2 v = 1 ×80
v = 40 m/sec
total energy of pieces
× 2 × 40 × 40 + × 1 × 80 × 80 = 1600 + 3200 = 4800 J = 4.8kj
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