KinematicsHard
Question
A particle is projected from a horizontal plane (x - z plane ) such that its velocity vector at time to is given by 
= aî + (b - ct)ĵ. Its range on the horizontal plane is given by : -
= aî + (b - ct)ĵ. Its range on the horizontal plane is given by : -Options
A.
B.
C.
D.None
Solution
= aî + (b - ct)ĵTime to reach maximum height (when ĵ comp. of velocity becomes zero)
∴ b - ct = 0 ⇒ t =
∴ Time of flight = 
Range = horizontal velocity × Time of flight = a ×
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