KinematicsHard
Question
The position vector of a particle is given as = (t2 - 4 + 6)î + (t2)ĵ. The time after time which the velocity vector and acceleration vector becomes perpendicular to each is equal to : -
Options
A.1 sec
B.2 sec
C.1.5 sec
D.Not possible
Solution
= (t2 + 4t + 6) î + t2 ĵ ; v = (2t - 4) î + 2t ĵ
= 2(î + ĵ) ; when ⊥
then . = 0 ; t = 1s
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