KinematicsHard
Question
A, B & C three objects each with constant velocity. A’s speed is 10 m/s in a direction
. The vorticity of B relative to A is 6 m/s at an angle of, cos-1(15/24) to PQ. The velocity of C relative to B is 12 m/s in a direction
. Then the magnitude of the velocity of C is :-
Options
A.5 m/s
B.2
m/s
C.3 m/s
D.4 m/s
Solution
|
| = 10 m/s

= 12(-î) + 6 ×
(î) +
+ 10î
=
|
| =
= 3m /s
= 12(-î) + 6 ×
=
|
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