KinematicsHard
Question
A student is standing at a distance of 50 meter from the bus. As. the bus begins its motion with an acceleration of 1 ms-2 the student starts running towards the bus with a uniform velocity u. Assuming the motion to be along a straight road, the minimum value of u, so that the student is able to catch the bus is
Options
A.8 ms-1
B.5 ms-1
C.12 ms-1
D.10 ms-1
Solution
Let the student travels distance s1 in time t and catches the bus.
s1 = ut ......(1)
Distance traveled by the bus in time t
s2 = 0 +
at2 ......(2)The student is able to each the bus if.
s1 = d + s2
ut = d +
1 × 12or, t2 - 2ut + 2d = 0
Solving the quadratic equation
t = - 2 ±
= - 2 ± 2
For t to be real
u ≥
≥
= 10m/s.Create a free account to view solution
View Solution FreeMore Kinematics Questions
In the figure shown the acceleration of A is = 15î + 15ĵ then the acceleration of B is (A remains in contact)I...A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 seconds, the next 5 seconds and the...A ball is dropped from the top of a building. The ball takes The ball 0.5 s to fall the 3m length of a window some dista...A particle has an initial velocity of (3î + 4ĵ) m/s and a constant acceleration of (4î - 3ĵ) m/s2. I...A spot light S rotates in a horizontal plane with a constant angular velocity of 0.1 red /s The spot of light ? P move a...