KinematicsEasy
Question
A particle is thrown vertically upward. Its velocity at half of the height is 10 m/s, then the maximum height attained by it will be :(g = 10m/s2)
Options
A.10m
B.20m
C.15m
D.25m
Solution
let maximum height be H
from the formula, v2 = u2 - 2gs
(10)2 = u2 - 2gh/2 = u2 - gH .....(1)
for attaining maximum height, v = 0
0 = u2 - 2gH/2 = u2 - gH
putting the value of u2 in (1),
100 = 2gH - gH = gH
H =
10 meter
from the formula, v2 = u2 - 2gs
(10)2 = u2 - 2gh/2 = u2 - gH .....(1)
for attaining maximum height, v = 0
0 = u2 - 2gH/2 = u2 - gH
putting the value of u2 in (1),
100 = 2gH - gH = gH
H =
10 meterCreate a free account to view solution
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