JEE AdvancedElectrochemistryHard
Question
Standard electrode potential for Sn4+ / Sn2+ couple is +0.15 V and that for the Cr3+ / Cr couples is - 0.74. These two couples in their standard state are connected to make a cell. The cell potential will be
Options
A.+ 0.89 V
B.+ 0.18 V
C.+ 1.83 V
D.+ 1.199 V
Solution
EoSn4+/Sn2+ = + 0.15 V
EoCr3+/Cr = - 0.74 V
EoCell = Eocathode(RP) - Eoanode(RP)
= 0.15 - ( - 0.74 )
= + 0.89 V .
EoCr3+/Cr = - 0.74 V
EoCell = Eocathode(RP) - Eoanode(RP)
= 0.15 - ( - 0.74 )
= + 0.89 V .
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
Given below are the half-cell reactions Mn2+ + 2e- → Mn ; Eo = - 1.18 V (Mn3+ + e- → Mn2+) ; Eo = + 1.51 V T...The following data are obtained in an experiment Solution Conductivity0.01 M HA 3.8 × 10-5Ω-1cm-1100 ml of 0.0...What will be the emf for the given cell Pt | H2 (P1) |H+ (aq) | | H2 (P2)| Pt...ᐃG is the available energy (energy produced) during the electrochemical reaction in galvanic cell which can be con...A certain current liberated 0.504 g of hydrogen in 2 hours. How many grams of copper can be liberated by the same curren...