ElectrochemistryHard
Question
The molar conductance of a 0.01 M solution of acetic acid was found to be 16.30 Ω−1 cm−1 mol−1 at 25°C. The ionic conductance of hydrogen and acetate ions at infinite dilution are 349.8 and 40.9 Ω−1 cm−1 mol−1, respectively, at the same temperature. What percentage of acetic acid is dissociated at this concentration?
Options
A.0.04172%
B.4.172%
C.41.72%
D.0.4172%
Solution
$\alpha = \frac{\Lambda_{m}}{\Lambda_{m}^{o}} = \frac{16.30}{(349.8 + 40.9)} = 0.04172\text{ or 4.172\%}$
Create a free account to view solution
View Solution FreeMore Electrochemistry Questions
In an electrolytic cell of Ag/AgNO3/Ag, when current is passed, the concentration of AgNO3...In an analytical determination of arsenic, a solution containing arsenious acid, H3AsO3, KI and a small amount of starch...For a closed-circuit Daniell cell, which of the following plots is the accurate one at a given temperature?...At what pH does the potential (EMF) for the disproportionation of chlorine change from a negative value to a positive va...Calculate the quantity of electricity that would be required to reduce 12.3 g of nitrobenzene to aniline if the current ...