ElectrochemistryHard
Question
If 0.224 L of H2 gas is formed at the cathode, the volume of O2 gas formed at the anode under identical conditions, is
Options
A.0.224 L
B.0.448 L
C.0.112 L
D.1.12 L
Solution
equivalence of H2 = equivalence of O2
× 2 = 
× 4
0.112 litre = volume of O2.
× 2 = × 40.112 litre = volume of O2.
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