Chemical Kinetics and Nuclear ChemistryMedium

Question

The energies of activation for forward and reverse reactions for A2 + B2 ⇋ 2AB are 180 kJ mol-1 2AB are 180 kJ mol-1 respectively. The presence of catalyst lowers the activation energy of both (forward and reverse) reactions by 100 kJ mol-1. The enthalpy change of the reaction (A2 + B2 → 2AB) in the presence of catalyst will be (in kJ mol-1)

Options

A.300
B.120
C.280
D.20

Solution

       
So, ᐃHReaction = Ef - Eb
= 80 - 100 = - 20
Hence, (4) is correct.

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