Current Electricity and Electrical InstrumentMedium
Question
Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are R1 and R2 (R2 > R1). If the potential difference across the source having internal resistance R2 is zero, then
Options
A.R = R2 × (R1 + R2)/R2 - R1)
B.R = R2 - R1
C.R = R1R2 /(R1 + R2)
D.R = R1R2 /(R2 - R1)
Topic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions
More Current Electricity and Electrical Instrument Questions
Three copper rods are subjected to different potential difference. Compare the drift speed of electrons through them. As...The resistivity of a wire depends on its : -...In a potentiometer wire experiment the emf of a battery in the primary circuit is 20V and its internal resistances is 5&...In fig. battery E is balanced on 55 cm length of potentiometer wire but when a resistance of 10 Ω is connected in p...The given Wheatstone bridge is showing no deflection in the galvanometer joined between the points B and D (Figure). Cal...
