Current Electricity and Electrical InstrumentHard
Question
Two sources of equal emf are connected to an external resistance R. The internal resistance of the two sources are R1 and R2 (R2 > R1). If the potential difference across the source having internal resistance R2 is zero, then
Options
A.R = R2 × (R1 + R2)/R2 - R1)
B.R = R2 - R1
C.R = R1R2 /(R1 + R2)
D.R = R1R2 /(R2 - R1)
Topic: Current Electricity and Electrical Instrument·Practice all Current Electricity and Electrical Instrument questions
More Current Electricity and Electrical Instrument Questions
A potentiometer circuit is set up as shown. the potential gradient, across the potentiometer wire, is k volt/cm and the ...Which one of the following is not a measurable quantity?...A heater coil is cut into two equal parts and only one part is now used in the heater. The heat generated will now be...R = ⇒ R ∝ L2The equivalent resistance between the points A and B is -...The length of a potentiometer wire is l.A cell of emf E is balanced at a length l/3 from the positive end of the wire. I...
