ThermodynamicsHard
Question
Two moles of helium gas are taken over the cycle ABCDA, as shown in the P - T diagram.
The work done on the gas in taking it from D to A is
The work done on the gas in taking it from D to A is
Options
A.- 414 R
B.+ 414 R
C.- 690 R
D.+ 690 R
Solution
At constant temperature (isothermal process)
WDA = nRT In
= 2.303 × 2R × 300 log 
= 2.303 × 600Rlog
= 0.693 × 600Rlog 600 R = - 414 R.
WDA = nRT In
= 2.303 × 2R × 300 log = 2.303 × 600Rlog
= 0.693 × 600Rlog
600 R = - 414 R.Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
In a water fall the water falls from a height of 100 m. If the entire energy of water is converted into heat. The rise i...If the temperature of a black body increases from 7oC to 287oC, then the rate of emission of radiation energy is :...If ᐃU and ᐃW represented the increases in internal energy and work done by the system respectively in a ther...A black body is heated from 27oC to 127oC. The ratio of their energies of radiation emitted will be:...In an adiabatic change, the pressure and temperature of a monoatomic gas are related with relation as P ∝ TC, wher...