ThermodynamicsHard
Question
Two moles of helium gas are taken over the cycle ABCDA, as shown in the P - T diagram.
The work done on the gas in taking it from D to A is
The work done on the gas in taking it from D to A is
Options
A.- 414 R
B.+ 414 R
C.- 690 R
D.+ 690 R
Solution
At constant temperature (isothermal process)
WDA = nRT In
= 2.303 × 2R × 300 log 
= 2.303 × 600Rlog
= 0.693 × 600Rlog 600 R = - 414 R.
WDA = nRT In
= 2.303 × 2R × 300 log = 2.303 × 600Rlog
= 0.693 × 600Rlog
600 R = - 414 R.Create a free account to view solution
View Solution FreeMore Thermodynamics Questions
When 1 kg of ice at 0oC melts to water at 0oC, the resulting change in its entropy, taking latent heat of ice to be 80 c...Three objects colored black, gray and white can withstand hostile conditions upto2800oC. These objects are thrown into a...An ideal black-body at room temperature is thrown into a furnace. It is observed that...A thermodynamic system undergoes cyclic process ABCDA as shown in figure. The work done by the system in the cycle is...The molar specific heat under constant pressure of oxygen is CP = 7.03 cal/mole k. The quantity of heat required to rais...