ThermodynamicsHard
Question
Two moles of helium gas are taken over the cycle ABCDA, as shown in the P - T diagram.
The work done on the gas in taking it from D to A is
The work done on the gas in taking it from D to A is
Options
A.- 414 R
B.+ 414 R
C.- 690 R
D.+ 690 R
Solution
At constant temperature (isothermal process)
WDA = nRT In
= 2.303 × 2R × 300 log 
= 2.303 × 600Rlog
= 0.693 × 600Rlog 600 R = - 414 R.
WDA = nRT In
= 2.303 × 2R × 300 log = 2.303 × 600Rlog
= 0.693 × 600Rlog
600 R = - 414 R.Create a free account to view solution
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