JEE Advanced | 2018Gaseous StateHard

Question

A reversible cyclic process for an ideal gas is shown below. Here, P , V and T are pressure , Volume and temperature , respectively. The thermodynamic parameters q, w, H and U are heat, work, enthalpy and internal energy, respectively

.
The correct option(s) is (are)

Options

A.

qAC = ∆ UBC and wAB = P2 (V2 – V1)

 

B.

wBC = P2 (V2 – V1) and qBC = ∆HAC

C.

∆HCA < ∆UCA and qAC = ∆UBC

D.

qBC = ∆HAC and ∆HCA > ∆UCA
 

Solution

AC→ Isochoric
AB→Isothermal
BC →Isobaric
# qAC= ∆UBC = nCV (T2 – T1)
WAB = nRT1 ln (v2\v1)                                 A (wrong)
# qBC = ∆HAC = nCP (T2 – T1)
WBC = – P2(V1 – V2)                                  B (correct)
# nCP (T1–T2) < nCV(T1 – T2)                    C (correct)
∆HCA < ∆UCA

# D (wrong)
 

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