NEET | 2016Atomic StructureEasy

Question

When an α-particle of mass ‘m’ moving with velocity ‘v’ bombards on a heavy nucleus of charge ‘Ze’, itsdistance of closest approach from the nucleus depends on m as:

Options

A.

1/m

B.

1m

C.

1/m2

D.

m

Solution

At the distance of lowest approach, total K.E. of α -particle changes to P.E. so
12mv2=KQ.qr=K(ze) (2e)r
r=4K ze2mv2 ⇒ r ∝1m
r∝1m

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